LeetCode 1108: Defanging an IP Address

Meta Data

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Difficulty: easy First Attempt: 2022-10-18

• Submissions: Accepted (first try)

Approach

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Replace every . with [.], either with one replace or by building the result character by character in a list (String Template 1).

My Solution

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class Solution:
    def defangIPaddr(self, address: str) -> str:
        return address.replace(".", "[.]")

Complexity

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Time O(n), space O(n).

Mistakes to Avoid

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• replace returns a new string; the original is unchanged.

Interview Explanation

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I replace each dot with a bracketed dot in one replace call, in O(n).