<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Floyds-Cycle-Finding-Algorithm on</title><link>https://h30306.github.io/blog/zh-tw/tags/floyds-cycle-finding-algorithm/</link><description>Recent content in Floyds-Cycle-Finding-Algorithm on</description><generator>Hugo -- gohugo.io</generator><language>zh-tw</language><managingEditor>hwork0511@gmail.com (Wei Yi Chung)</managingEditor><webMaster>hwork0511@gmail.com (Wei Yi Chung)</webMaster><copyright>© 2026 Wei Yi Chung</copyright><lastBuildDate>Mon, 14 Nov 2022 00:00:00 +0000</lastBuildDate><atom:link href="https://h30306.github.io/blog/zh-tw/tags/floyds-cycle-finding-algorithm/index.xml" rel="self" type="application/rss+xml"/><item><title>LeetCode 142: Linked List Cycle II</title><link>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-142/</link><pubDate>Mon, 14 Nov 2022 00:00:00 +0000</pubDate><author>hwork0511@gmail.com (Wei Yi Chung)</author><guid>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-142/</guid><description>LeetCode 142 解題筆記：快慢指針相遇後，一個回到 head，兩個都一次一步，再相遇的地方就是環的入口</description><media:content xmlns:media="http://search.yahoo.com/mrss/" url="https://h30306.github.io/blog/leetcode/leetcode-142/featured.png"/></item><item><title>LeetCode 202: Happy Number</title><link>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-202/</link><pubDate>Sun, 21 Aug 2022 00:00:00 +0000</pubDate><author>hwork0511@gmail.com (Wei Yi Chung)</author><guid>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-202/</guid><description>LeetCode 202 解題筆記：一直取位數平方和，會走到 1 或進入環；用集合記看過的數，或用快慢指針判圈</description><media:content xmlns:media="http://search.yahoo.com/mrss/" url="https://h30306.github.io/blog/leetcode/leetcode-202/featured.png"/></item><item><title>LeetCode 141: Linked List Cycle</title><link>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-141/</link><pubDate>Sat, 20 Aug 2022 00:00:00 +0000</pubDate><author>hwork0511@gmail.com (Wei Yi Chung)</author><guid>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-141/</guid><description>LeetCode 141 解題筆記：Floyd 判圈，快指針一次兩步、慢指針一次一步，有環就一定會相遇；兩個都要從自己的位置往前走</description><media:content xmlns:media="http://search.yahoo.com/mrss/" url="https://h30306.github.io/blog/leetcode/leetcode-141/featured.png"/></item></channel></rss>