<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Minimax-Algorithm on</title><link>https://h30306.github.io/blog/zh-tw/tags/minimax-algorithm/</link><description>Recent content in Minimax-Algorithm on</description><generator>Hugo -- gohugo.io</generator><language>zh-tw</language><managingEditor>hwork0511@gmail.com (Wei Yi Chung)</managingEditor><webMaster>hwork0511@gmail.com (Wei Yi Chung)</webMaster><copyright>© 2026 Wei Yi Chung</copyright><lastBuildDate>Tue, 23 Aug 2022 00:00:00 +0000</lastBuildDate><atom:link href="https://h30306.github.io/blog/zh-tw/tags/minimax-algorithm/index.xml" rel="self" type="application/rss+xml"/><item><title>LeetCode 292: Nim Game</title><link>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-292/</link><pubDate>Tue, 23 Aug 2022 00:00:00 +0000</pubDate><author>hwork0511@gmail.com (Wei Yi Chung)</author><guid>https://h30306.github.io/blog/zh-tw/leetcode/leetcode-292/</guid><description>LeetCode 292 解題筆記：剩 4 的倍數顆石頭的人必輸，所以 n % 4 != 0 時先手贏</description><media:content xmlns:media="http://search.yahoo.com/mrss/" url="https://h30306.github.io/blog/leetcode/leetcode-292/featured.png"/></item></channel></rss>